Makarychev, N.g Mindiuk.k.i. Neshkov, S.b Suvorova - Gdz Po Algebre Iu.n.

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x2−9=(x−3)(x+3)x squared minus 9 equals open paren x minus 3 close paren open paren x plus 3 close paren

Divide both the numerator and denominator by

x2−92x+6the fraction with numerator x squared minus 9 and denominator 2 x plus 6 end-fraction Use the difference of squares formula

(x−3)(x+3)2(x+3)=x−32the fraction with numerator open paren x minus 3 close paren open paren x plus 3 close paren and denominator 2 open paren x plus 3 close paren end-fraction equals the fraction with numerator x minus 3 and denominator 2 end-fraction ✅ The simplified expression is